ax2 + bx + c = 0
x = −b ± √b2 − 4ac2a
x = −b ± √b2 − 4 × a × c2 × a
b2 − 4ac = one number
x = −b + √number2a or x = −b − √number2a
x = answer 1 or x = answer 2
a minus in front makes b or c negative
a negative number goes in brackets
c negative? then the 4ac adds on
usually 2 decimal places