Equations: the unknown on both sides
The Maths Habit
Solve 5(x + 2) = 35
x = 5
Solve 4(x − 3) = 18
x = 7.5
Solve 2(3x + 4) = 2
x = −1
Left: 5 bags and 2 marbles.
Right: 3 bags and 12 marbles.
Bags hold the same. It balances.
What could you take off both sides?
3 bags, or 2 marbles: 5 in a bag
Simplify
5x − 2x
3x
7x − x
6x
4x − 9x
−5x
3x − 3x
0
Which side has fewer x?
2x + 11 = 6x + 3
The left
Solve 5x + 2 = 3x + 12
− 3x both sides2x + 2 = 12− 2 both sides2x = 10÷ 2 both sidesx = 5
Answerx = 5
Solve 6x + 4 = 2x + 16
− 2x both sides4x + 4 = 16− 4 both sides4x = 12÷ 4 both sidesx = 3
Answerx = 3
Solve 5x + 2 = 3x + 12
− 3x both sides2x + 2 = 12− 2 both sides2x = 10÷ 2 both sidesx = 5
Answerx = 5
Solve 7x + 1 = 4x + 13
− 4x both sides3x + 1 = 13− 1 both sides3x = 12÷ 3 both sidesx = 4
Answerx = 4
Solve 5x + 2 = 3x + 12
− 3x both sides2x + 2 = 12− 2 both sides2x = 10÷ 2 both sidesx = 5
Answerx = 5
Solve 6x + 3 = 2x + 27
− 2x both sides4x + 3 = 27− 3 both sides4x = 24÷ 4 both sidesx = 6
Answerx = 6
Solve 5x + 2 = 3x + 12
− 3x both sides2x + 2 = 12− 2 both sides2x = 10÷ 2 both sidesx = 5
Answerx = 5
Solve 2x + 19 = 5x + 4
− 2x both sides19 = 3x + 4− 4 both sides15 = 3x÷ 3 both sidesx = 5
Answerx = 5
Solve 5x + 2 = 3x + 12
− 3x both sides2x + 2 = 12− 2 both sides2x = 10÷ 2 both sidesx = 5
Answerx = 5
Solve 4x + 9 = x + 15
− x both sides3x + 9 = 15− 9 both sides3x = 6÷ 3 both sidesx = 2
Answerx = 2
I think of a number. Five times my number add 2 is the same as three times my number add 16. What is my number?
7
Solve 3(x + 2) = x + 14
x = 4
Solve 7x + 4 = 3x + 24
x = 5
Solve 4x + 25 = 9x + 5
x = 4
Solve 5(x − 1) = 2x + 13
x = 6
Exit tickets to print